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Google Maps Routes
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Google Maps Routes

Google Maps Routes

mcdowell/google-maps-route-scraper
Try for free

3 days trial then $30.00/month - No credit card required now

A flexible scraper that returns the quickest route between two locations. Can filter paths by avoiding `Ferries`, `Highways` and `Tolls`

The code examples below show how to run the Actor and get its results. To run the code, you need to have an Apify account. Replace <YOUR_API_TOKEN> in the code with your API token, which you can find under Settings > Integrations in Apify Console. Learn mode

Node.js

Python

curl

1import { ApifyClient } from 'apify-client';
2
3// Initialize the ApifyClient with your Apify API token
4const client = new ApifyClient({
5    token: '<YOUR_API_TOKEN>',
6});
7
8// Prepare Actor input
9const input = {
10    "startUrls": [
11        {
12            "url": "https://www.google.com/maps/dir/Orlando,+FL,+USA/Oak+Ridge/@28.50464,-81.4524678,13z/am=t/data=!4m13!4m12!1m5!1m1!1s0x88e773d8fecdbc77:0xac3b2063ca5bf9e!2m2!1d-81.3789269!2d28.5383832!1m5!1m1!1s0x88e77c21b7cf3a27:0xda788a24a75ae598!2m2!1d-81.4245155!2d28.4711157"
13        }
14    ]
15};
16
17(async () => {
18    // Run the Actor and wait for it to finish
19    const run = await client.actor("mcdowell/google-maps-route-scraper").call(input);
20
21    // Fetch and print Actor results from the run's dataset (if any)
22    console.log('Results from dataset');
23    const { items } = await client.dataset(run.defaultDatasetId).listItems();
24    items.forEach((item) => {
25        console.dir(item);
26    });
27})();
Developer
Maintained by Community
Actor metrics
  • 3 monthly users
  • 100.0% runs succeeded
  • 0.0 days response time
  • Created in Aug 2022
  • Modified 2 months ago
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